Three numbers are in the ratio 3:4:5. The sum of their cube is 0.001728. Find the numbers.
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Answer:
1st no.=0.06
2nd no.=0.08
3rd no.=0.1
Step-by-step explanation:
Let the ratio be x.
1st no. 3x
2nd no. 4x
3rd no. 5x
According to question:
(3x)³+(4x)³+(5x)³ = 0.001728
27x³+64x³+125x³= 0.001728
216x³= 0.001728
(6x)³ = (0.12)³
6x = 0.12 (cube cancelled)
x = 0.02
1st no.= 3×0.02
=0.06
2nd no.= 4×0.02
=0.08
3rd no.= 5×0.02
= 0.1
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