three numbers are in the ratio 3:5:9. find the largest number, given that sum of squares of the number is 460
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Answered by
40
Begin by assuming the numbers.
Since the ratio is given as 3 : 5 : 9,
Let the numbers be 3x, 5x and 9x.
According to the question we can easily derive the below written equation,
( 3x ) ^ 2 + ( 5x ) ^ 2 + ( 9x ) ^ 2 = 460
9x^2 + 25x^2 + 81x^2 = 460
115x^2 = 460
x^2 = 460 / 115
x^2 = 4
x = √4
x = 2
Hence,
The largest number = 9x = 9 * 2 = 18
Similarly, if you like you may find other numbers too ^_^
Since the ratio is given as 3 : 5 : 9,
Let the numbers be 3x, 5x and 9x.
According to the question we can easily derive the below written equation,
( 3x ) ^ 2 + ( 5x ) ^ 2 + ( 9x ) ^ 2 = 460
9x^2 + 25x^2 + 81x^2 = 460
115x^2 = 460
x^2 = 460 / 115
x^2 = 4
x = √4
x = 2
Hence,
The largest number = 9x = 9 * 2 = 18
Similarly, if you like you may find other numbers too ^_^
Answered by
11
Hope that answer help you dear friend
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