Three numbers are in the ratio 3:7:9. If 5 is subtracted from the second, the resulting numbers are in AP. Find the original numbers.
Answers
Answered by
84
so let the three numbers are 3x , 7x , 9x
so according to question
3x , 7x - 5 , 9x are AP
2(7x - 5) = 9x + 3x
⇒ 14x - 10 = 12x
⇒ 2x = 10
⇒ x = 5
so the original numbers are
3 x 5 = 15
7 x 5 = 35
9 x 5 = 45
so according to question
3x , 7x - 5 , 9x are AP
2(7x - 5) = 9x + 3x
⇒ 14x - 10 = 12x
⇒ 2x = 10
⇒ x = 5
so the original numbers are
3 x 5 = 15
7 x 5 = 35
9 x 5 = 45
Answered by
31
so let the three numbers are 3x , 7x , 9x
so according to question
3x , 7x - 5 , 9x are AP
2(7x - 5) = 9x + 3x
⇒ 14x - 10 = 12x
2x=10
x=5
the real numbers are
3 x 5 = 15
7 x 5 = 35
9 x 5 = 45
the original numbers are 15 35 45
so according to question
3x , 7x - 5 , 9x are AP
2(7x - 5) = 9x + 3x
⇒ 14x - 10 = 12x
2x=10
x=5
the real numbers are
3 x 5 = 15
7 x 5 = 35
9 x 5 = 45
the original numbers are 15 35 45
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