Question

Three numbers are in the ratio 4:3:2. If the sum of their cubes is 2.673, find the smallest of these three numbers. Express your answer as a decimal

Answer 1

Given: Three numbers are in the ratio 4:3:2. If the sum of their cubes is 2.673.

To find:  The smallest of these three numbers.

Solution:

• Now we have given the ratio 4:3:2

• Let the common ratio be x, then the numbers are 4x, 3x, 2x.

• Now we have given that the sum of their cubes is 2.673 so:

                       (4x)^3 + (3x)^3 + (2x)^3 = 2.673

• Expanding it, we get:

                       (64 + 27 + 8)x^3 = 2.673

                       99x^3 = 2.673

                       x^3 = 2.673/99

                       x^3 = 0.027

                       x = 0.3

• Putting the value of x in the numbers, we get:

                       4x = 4(0.3) = 1.2

                       3x = 3(0.3) = 0.9

                       2x = 2(0.3) = 0.6

• So the smallest number is 0.6

Answer:

                So the smallest number is 0.6 .

Answer 2

Answer:

0.6

Step-by-step explanation: mark me brainliest XD