Math, asked by sami34, 1 year ago

three numbers are in the ratio 4:5:6 .if the sum of largest and smallest equals the sum of the third and 55 find the numbers

Answers

Answered by adarshpandey4
10
4x+6x=5x+55
10x=5x+55
10x-5x=55
5x=55
x=55/5
x=11
4x=4×11=44
5x=5×11=55
6x=6×11=66
Answered by Bunti360
2
I can say that your question is wrong and it should be Sum of second and 55, So by the new question the solution is ,

Let the greatest common divisor of the numbers be x,

Now, The numbers will become,
4x, 5x, 6x,

According to it, The greatest number is 6x, and the smallest is 4x,

Now, By the question, We can write that,

6x + 4x = 5x + 55,
=> 10x = 5x + 55,
=> 5x = 55,
=> x = 11,

Now , The numbers are,

4*11, 5*11, 6*11,
=> 44,55,66,

So here are the numbers which we needed,

If you think your question is right, Then, The answer would be,

4x = 55,
=> x = 55/4,

And then the numbers would be ,

55, 68.75, 82.5,

So therefore the answer if the question is wrong is 44, 55, 66, And if the question is right, Then the answer is 55, 68.75, 82.5,

Hope you understand, Have a great day !

Thanking you, Bunti 360 !
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