Question

Three numbers are in the ratio 4:5:6. If the sum of the largest and the smallest
number equals the sum of the third plus 55, find the numbers.​

Answer 1

Answer:

1st no.= 44

2nd no.=55

3rd no.= 66

Step-by-step explanation:

Let the three numbers be 4x,5x and 6x respectively.

According to the question-

6x+4x=5x+55

10x−5x=55

⇒x=55/5

x =11

Therefore,

First no. =4×11=44

Second no. =5×11=55

Third no. =6×11=66

Hence the three numbers are 44,55 and 66.

Hope u understand the solution ☺️☺️.....

Answer 2

Step-by-step explanation:

let the number be 4x,5x,6x

According to the question

4x+6x=5x+55

10x-5x=55

5x=55

x=11

The first number = 4x=4×11

=44

The second number = 5x=5×11

=55

The third number = 6x= 6×11

=66

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