Three numbers are in the ratio 4:5:7. If the sum of the largest and the smallest number is 72 more than the third
number, find the numbers.
Answers
Answered by
3
Answer:
Let the three numbers be 4x, 5x and 7x
According to the question,
7x + 4x= 72 + 5x
7x + 4x - 5x= 72
11x - 5x= 72
6x= 72
x= 72/6
x= 12
Therefore,
the numbers will be (4x12)= 48, (5x12)= 60 and (7x12)= 84
Answered by
0
Answer:
Step-by-step explanation:
Similar questions