Math, asked by alphaphilip28, 4 days ago

Three numbers are in the ratio 5:7:12 and the sum of the first and third numbers is greater than the second by 50. The sum of the three numbers is ​

Answers

Answered by Anonymous
0

Step-by-step explanation:

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Answered by bagkakali
0

Answer:

let the numbers are 5x , 7x , 12x

according to question

5x+12x=7x+50

=> 17x-7x=50

=> 10x=50

=> x=50/10

=> x=5

so the numbers are

5×5=25 , 7×5=35 , 12×5=60

so the sum of the three numbers is

(5+7+12)×5=24×5=120

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