Question

Three numbers are in the ratio of 2:3:4. The sum of their cube is 33957. Find the largest number.

Answer 1

Answer:

let the number be 2x , 3x and 4x

according to question,

(2x)³ +( 3x)³ + (4x)³ = 33957

8x³ + 27x³ + 64x³ = 33957

99x³ = 3395

x³ = 33975/99

x³ = 343

x³ = 7³

x = 7

so,

first no. = 7× 2= 14

second number= 7×3. = 21

third number= 7× 4 = 28

Answer 2

Answer:

here's the answer

Step-by-step explanation:

(2x*3)+(3x*3)+(4x*3)=33957

8x*3+27x*3+64x*3=33957

by solving this equation the value of x come

then the largest is 4x put the value of x in this equation

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