Question

Three numbers are in the ratio of 3: 4 :5 respectively. If the sum of the first and third numbers is more than the second number by 52, then which will be the largest number? ( A ) 65 ( B ) 52 ( C ) 72 ( D ) 67

Answer 1

Answer:

let the common multiples of the numbers be x.

so the numbers are 3x,4x5x and

now ,

3x+5x =4x+52

8x-4x =52

4x=52

x=13

largest number is 5x =65

Answer 2

Step-by-step explanation:

Let the three numbers be 3x, 4x and 5x.

According to the given information:

3x + 5x = 4x + 52

$\therefore \: 8x = 4x + 52 \\ \therefore \: 8x - 4x = 52 \\ \therefore \: 4x = 52 \\ \therefore \: x = \frac{52}{4} \\ \huge \boxed{\therefore \: x = 13} \\ \therefore \: \\ 3x = 3 \times 13 = 39 \\ 4x = 4 \times 13 = 52 \\ 5x = 5 \times 13 = 65$

Thus the largest number is 65.

Hence, option (A) 65 is the correct answer.