Question

three numbers are in the ratio of 4:5:6.if the sum of largest and the smallest is the smallest is equal to the twice of 55.find the number
please give me the answer ​

Answer 1

Answer:

let the common multiple be x

the numbers will be 4x,5x, 6x

4x+6x=5x+55

10x=5x+55

5x=55

x=11

44,55,66 are the numbers

Answer 2

Step-by-step explanation:

let the number be x

ratio = 4:5:6 = 4x:5x:6x

largest number = 6x

smallest number = 4x

twice of 55 = 2 × 55 = 110

sum of the largest number and smallest number = twice of 55

According to the problem....

6x + 4x = 2 × 55

10x = 110

x = 110/10

x = 11

therefore,

the number is = x = 11

the remaining numbers are ,

1. 4x = 4×11 = 44
2. 5x = 5×11 = 55
3. 6x = 6×11 = 66