three numbers are in the ratio of 4:5:6.if the sum of the laregest and the smallest equals the aum of the third and 55.find the numbers
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Answered by
1
4x +5x+6x=55
15x=55
x=55÷15
x=11÷3
x=3.10
15x=55
x=55÷15
x=11÷3
x=3.10
Answered by
5
let three no. be 4x,5x,6x
6x+4x=55+5x
10x-5x=55
5x= 55
x=11
no.are 4*11,5*11,6*11=44,55,66
6x+4x=55+5x
10x-5x=55
5x= 55
x=11
no.are 4*11,5*11,6*11=44,55,66
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