Question

Three numbers are in the ratio of 4:5:6. If the sum of the largest and the smallest equals
the sum of the third and 55, find the numbers.
​

Answer 1

Step-by-step explanation:

Answer

Given that the three numbers are in the ratio 4:5:6.

Let the three numbers be 4x,5x and 6x respectively.

Now,

According to the question-

6x+4x=5x+55

10x−5x=55

⇒x=

5

55

=11

Therefore,

First no. =4×11=44

Second no. =5×11=55

Third no. =6×11=66

Hence the three numbers are 44,55 and 66.

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Answer 2

Let the numbers be 4x, 5x and 6x

According to the question we can write as 

6x+4x=5+55

On rearring we can write as 

10x−5x=55

5x=55

x=55/5=11

So the numbers are 44, 55 and 66