three numbers are in the ration 3:7:9. if 5 is subtracted from the second the resulting numbers are in ap. find the original no .
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Let ,the three numbers are 3x,7x,9x
if 5 is subtracted = 7x - 5( A.P)
b= a + c/2
7x - 5 = (3x + 9x )/2
2(7x - 5) = 12x
14x - 10 = 12x
14x - 12x = 10
2x = 10 => 10/2 =5
Numbers are 3(5), 7(5), 9(5)= 15, 35, 45
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