Question

three numbers are on the ratio 4:5:6 . the sum of their cubes is 87480 . find the numbers​

Answer 1

Let first no be 4x, second no 5x ,and third no 6x.

(4x)^3 + (5x)^3 +(6x)^3 = 87,480

64x^3 + 125x^3 + 216x^3 = 87,480

405x^3 = 87,480

x^3 = 216

x= 6

First number = 4*6 = 24

second no = 5*6 = 30

third no = 6*6 = 36.

Answer 2

let the no. be 4x , 5x, 6x

product of no. = 87480

4x × 5x × 6x = 87480

120x3 = 87480

x2 = 120 / 87480

x3 = 729

x - 9

4x = 4 × 9 = 36

5x = 5 × 9 = 45

6x = 6 × 9 = 54

hence numbers are 36 , 45 , 54