Question

Three numbers are selected from 1 to 8.
What is the probability for the 3 selected
number to be consecutive c
3 4 5 6 7 8
8
3
5
(a)
(b)
28
28
8
w
9
7
(C)
28
(d)
28​

Answer 1

Answer:

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Answer 2

$\huge\mathcal{\fcolorbox{red}{gray}{\green{A}\pink{N}\orange{S}\purple{W}\red{E}\blue{R}{!}}}$

Total outcomes = 8

Favourable outcomes = 1

$\large\:P(E)\:=\: \frac{Favourable\: outcomes}{Total\:outcomes}$

=> $\huge\frac{1}{8}$