three numbers are to one another 2:3:4. the sum of their cubes is 131769. find the smallest numbers.
Answers
Answered by
4
Let the numbers be 2x,3x and 4x.
Given,
Sum of cubes=131769
We can write,
8x^3+27x^3 +64x^3=131769
or 99x^3=131769
or x^3= 131769÷ 99
or x^3=1331
or x=11
So,the numbers are 22,33,44.
the smallest number=22
Given,
Sum of cubes=131769
We can write,
8x^3+27x^3 +64x^3=131769
or 99x^3=131769
or x^3= 131769÷ 99
or x^3=1331
or x=11
So,the numbers are 22,33,44.
the smallest number=22
Answered by
3
Let the numbers be 2x, 3x, & 4x.
So, cube of these numbers will be 8x³, 27x³, 64x³ respectively.
A/Q,
➡ 8x³ + 27x³ + 64x³ = 131769
➡ 99x³ = 131769
➡ x³ = 131769/99
➡ x³ = 1331
➡ x = 11
So, the numbers are = 2x = 11*2 = 22
➡ 3x = 11*3 = 33
➡ 4x = 11*4 = 44.
Smallest no is 22.
So the required answer is 22.
Hope it will help you !!!
So, cube of these numbers will be 8x³, 27x³, 64x³ respectively.
A/Q,
➡ 8x³ + 27x³ + 64x³ = 131769
➡ 99x³ = 131769
➡ x³ = 131769/99
➡ x³ = 1331
➡ x = 11
So, the numbers are = 2x = 11*2 = 22
➡ 3x = 11*3 = 33
➡ 4x = 11*4 = 44.
Smallest no is 22.
So the required answer is 22.
Hope it will help you !!!
MSALMANALI:
thanks.......
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