Question

Three numbers are to one another 2:3:4. The sum of their cube is 0.334125. Find the numbers.

Answer 1

Let the numbers be 2a, 3a and 4a

According to question,

(2a)^3 + (3a)^3 + (4a)^3 = 0.334125

=> 8a^3 + 27a^3 + 64a^3 = 0.334125

=> 99a^3 = 0.334125

=> a^3 = 0.003375

=> a = 0.15

First number = 2 × 0.15 = 0.3

Second number = 3 × 0.15 = 0.45

Third number = 4 × 0.15 = 0.6

Answer 2

Let the numbers be 2a, 3a and 4a

According to question,

(2a)^3 + (3a)^3 + (4a)^3 = 0.334125

=> 8a^3 + 27a^3 + 64a^3 = 0.334125

=> 99a^3 = 0.334125

=> a^3 = 0.003375

=> a = 0.15

First number = 2 × 0.15 = 0.3

Second number = 3 × 0.15 = 0.45

Third number = 4 × 0.15 = 0.6