three numbers are to one another in the ratio 2:3:4. the sum of their cubes is 33957. find the numbers
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Answered by
19
Three numbers are in the ratio 2:3:4
Let the three numbers be 2x,3x,4x
The sum of their cubes = 33957
(2x)³+(3x)³+(4x)³ = 33957
8x+27x+64x = 33957
99x = 33957
x = 33957/99
x = 343
The numbers are
→ 2x = 2(343) = 686
→ 3x = 3(343) = 1029
→ 4x = 4(343) = 1372
Hope it helps
Let the three numbers be 2x,3x,4x
The sum of their cubes = 33957
(2x)³+(3x)³+(4x)³ = 33957
8x+27x+64x = 33957
99x = 33957
x = 33957/99
x = 343
The numbers are
→ 2x = 2(343) = 686
→ 3x = 3(343) = 1029
→ 4x = 4(343) = 1372
Hope it helps
Answered by
9
let the nos. be 2x, 3x and 4x
sum of nos. = 33957
(2x)²+(3x)²+(4x)²= 33957
8x+27x+64x= 33957
x= 33957/99
= 343
hence nos. will be 2x= 686
3x=1029
4x=1372
hope this will help...plz react thanks
sum of nos. = 33957
(2x)²+(3x)²+(4x)²= 33957
8x+27x+64x= 33957
x= 33957/99
= 343
hence nos. will be 2x= 686
3x=1029
4x=1372
hope this will help...plz react thanks
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