Math, asked by patilgaurav604, 11 months ago

three numbers bear a ratio of 2:3:4 to one another . if the sum of the reciprocals of the first and third number by 5/12. what is the second number ?

Answers

Answered by preranadas480
0

Answer:

Step-by-step explanation:

Let the

Attachments:
Answered by sharonr
1

The second number is 5.4

Solution:

Given that,

Three numbers are in ratio 2 : 3 : 4

Let the first number be 2x

Let the second number be 3x

Let the third number be 4x

The sum of the reciprocals of the first and third number by 5/12

\frac{1}{2x} + \frac{1}{4x} = \frac{5}{12} \\\\\frac{3}{4x} = \frac{5}{12} \\\\9 = 5x\\\\x = \frac{9}{5}

Thus the second number is:

second\ number = 3x = 3 \times \frac{9}{5} \\\\second\ number = \frac{27}{5} = 5.4

Thus the second number is 5.4

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