Question

Three numbers form a H.P. the sum of the numbers is 11 and the sum of their reciprocals is 1.1
one among those numbers is
1
13
2) 4
3)
4)
6
2​

Answer 1

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Answer 2

Given : Three numbers form a H.P. the sum of the numbers is 11 and the sum of their reciprocals is 1

To Find : one among those numbers is

3

4

6

2

Solution:

Let say three numbers  are

1/a  , 1/b . 1/c

Three numbers form a H.P.

=> a   , b & c are in ap

=> 2b  = a + c

1/a + 1/b  + 1/c  = 11

sum of their reciprocals is 1

=> a + b  + c  =  1

=> 2b + b = 1

=> 3b  = 1

=> 3 = 1/b

one number is  3.

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