Three numbers form an increasing G. P. If the middle term is doubled , then the new numbers are in A. P. Find the common ratio of the G. P.
Answers
Answered by
354
Hi, let the numbers be a, ar, ar^2 (r>1)
According to question,
a, 2ar, ar^2 are in A.P.
b-a=c-b
2b=a+c
Now! 2(2ar)=a+ar^2 (a not equal to 0)
4r=1+r^2
r^2-4r+1=0
Applying Quadratic equation! -b+/-√b^2-4ac÷2a
r=2+/-root of 3
r=2+root of 3 (+ only)
If you have any doubts, plz post it below. :)
According to question,
a, 2ar, ar^2 are in A.P.
b-a=c-b
2b=a+c
Now! 2(2ar)=a+ar^2 (a not equal to 0)
4r=1+r^2
r^2-4r+1=0
Applying Quadratic equation! -b+/-√b^2-4ac÷2a
r=2+/-root of 3
r=2+root of 3 (+ only)
If you have any doubts, plz post it below. :)
Abhinav2002:
Thank you very very very much
Answered by
0
Answer:
(a) 2 + √3
Step-by-step explanation:
Let the three numbers be a/r, a, ar
Since the numbers form an increasing GP, So r > 1
Now, it is given that a/r, 2a, ar are in AP
⇒ 4a = a/r + ar
⇒ r² – 4r + 1 = 0
⇒ r = 2 ± √3
⇒ r = 2 + √3 (Since r > 1)
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