Question

Three numbers in gp if we double midddle term we get ap then common ratio

Answer 1

three no. in GP are 
a, ar , ar2  (r>1
now Acc. to ques.
a, 2ar, ar2 are in AP
i.e   2ar - a = ar2-  2ar
  2r -1 = r2 -2r
  r2 -4r +1 =0
  r = 4 + root ( 16  - 4 )  /2
  = 4 + 2 root 3 / 2
  = 2 + root3

Answer 2

hello mate!!!!!!!!!!!!!!!!!

АпЗЩЁГ↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓

a, 2ar, ar^2 are in A.P.

b-a=c-b

2b=a+c

Now! 2(2ar)=a+ar^2  (a not equal to 0)

4r=1+r^2

r^2-4r+1=0

         Applying Quadratic equation! -b+/-√b^2-4ac÷2a

r=2+/-root of 3

r=2+root of 3    (+ only)

АпЗЩЁГ↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑

plz mark me brainliest!!!!!!!!!!!!!!!!!