Question

three numbers the ratio 3:5:7 and the average 60. find the smallest number?
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Answer 1

Given:

Ratio of three numbers is 3:5:7

The average of three numbers is 60

To find:

The smallest number.

Let the three numbers be, 3x, 5x, and 7x

Now,

Average= (Sum of given data)/number of given data

60 = (3x + 5x + 7x)/3

60*3 = 15x

180 = 15x

180/15 = x

12 = x

Thus, the value of x is 12.

Now the numbers are

3x = 3*12 = 36

5x = 5*12 = 60

7x = 7*12 = 84

Hence,

The smallest number is 36

Answer 2

Question Given :

• three numbers the ratio 3:5:7 and the average 60. find the smallest number?

Required Solution :

Value given to us :

• three numbers the ratio 3:5:7

Assumptions :

• Let the Number be 3x , 5x , 7x

According to Question :

• 60 = [ 3x + 5x + 7x ] / 3

• 60 × 3 = 15x

• 180 = 15x

• x = 180 / 15

• x = 12

Putting Value at place of x :

• First Number = 3 × 12 = 36

• Second Number = 5 × 12 = 60

• Third Number = 6 × 12 = 72

Hence :

• .°. Smallest Number is 36