Math, asked by srushpanjain3449, 11 months ago

Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is:

Answers

Answered by nitish60803
17

Answer:

SINCE NUMBER ARE CO PRIME , they contain only 1 as common factor.

middle number = HCF OF 551

Step-by-step explanation:

and HCF OF 1073

551= 19×29

1073 = 29×37

HCF = 29

first number - (551/29)= 19

third number - ( 1073/29)= 29

THEREFORE

required sum is - ( 19+29+37 = 85)

!!HOPE IT HELPS!!

Answered by Anonymous
1

Given :

•3 numbers which are co-prime to each other such that the product of the 1st two numbers is 551 and that of the last 2 is 1073.

To find :

• The sum of 3 numbers?

Calculations :

★ Taking HCF (Higest common factor) for 551 and 1073.

= HCF = 29 ---(1)

★ Dividing the first number and last number by the 29, we get:

= 551/29

= 19 ---(2)

= 1073/29

= 37 ---(3)

★ As per the last case, sum of three numbers, we get:

= 29 + 19 + 37

= 85

★ Therefore, the sum of three numbers is equal to 85.

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