Three numbers which are coprime to one another as such that the product of first 2 is 551 and that of the last two is 1073.find the sum of 3 nos
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HCF of 551 and 1073 is 29
so second number is 29
first number = 551 / 29 = 19
third number =1073 / 29 =37
so, required sum = 19 +29+ 37 =85
so second number is 29
first number = 551 / 29 = 19
third number =1073 / 29 =37
so, required sum = 19 +29+ 37 =85
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Given :
•3 numbers which are co-prime to each other such that the product of the 1st two numbers is 551 and that of the last 2 is 1073.
To find :
• The sum of 3 numbers?
Calculations :
★ Taking HCF (Higest common factor) for 551 and 1073.
= HCF = 29 ---(1)
★ Dividing the first number and last number by the 29, we get:
= 551/29
= 19 ---(2)
= 1073/29
= 37 ---(3)
★ As per the last case, sum of three numbers, we get:
= 29 + 19 + 37
= 85
★ Therefore, the sum of three numbers is equal to 85.
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