Math, asked by nikhilupadhyay076, 8 months ago


Three numbers whose HCF is 12 with 1 number being between 40 and 50.​

Answers

Answered by Anonymous
0

Answer:

36, 48, 60 is one possible selection of three such numbers.

Step-by-step explanation:

The three numbers need to be multiples of 12.

The one between 40 and 50 then has to be 48 = 4 × 12.

To make sure that the HCF is just 12 and not something larger, we can just take the others to be (something)×12 where (something) has no factor in common with 4 (since 48 = 4×12).  So 36 = 3×12 and 60 = 5×12 will do just fine.

So for the three numbers, one could take 36, 48, 60.

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