Three numbers whose sum is 18 are in A.P. If the first is increased by 1, the resulting numbers are in G.P. Find the numbers in A.P.
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Let the numbers are a-r,aanda+r.
Then, a+a-r+a+r=18⇒3a=18⇒a=6
We are given if we add 2,4 and 11 to these numbers, it will be in GP.So,
6+4
6-r+2
=
6+r+11
(6+4)
⇒
10
8-r
=
17+r
10
⇒(17+r)(8-r)=100
⇒r2+9r-136+100=0
⇒r2+9r-36=0
⇒(r+12)(r-3)=0
r=-12andr=3
When r=-12, then numbers are, 18,6,-6.
When r=3, then numbers are 3,6,9.
Explanation:
Hope it may help you..
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