Question

Three numbers whose sum is 21 are in ap if the product of the first and its third
numbers exeeds the second number by 6 find the Numbers

Answer 1

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KshitijakaHelping Hand

Let the 3 numbers be (a-d), a and (a + d).

According to the question,

a-d+a+a+d=21

then 3a=21

a=7

Also,

(a-d)(a+d)=a+6

a^2-d^2=a+6

from above a=7,putting here we get

d=+-6

If d = 6, then the numbers are 7 - 6, 7, 7 + 6 

 = 1, 7, 13

If d = -6, then the numbers are 7 - (-6), 7, 7 + (-6)

 = 13, 7, 1