Question

Three objects A, B, and C are arranged as shown in the fig. below. Calculate the force of gravitation between any two objects at a time and mention which of the two is the force of gravitation maximum.

Answer 1

Answer:

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Answer 2

Given:

Mass of object A = 30 Kg ,

                         B = 20 Kg ,

                         C = 40 Kg

Distance between AB = 15 m ,

                               BC = 10 m ,

                               AC = 20 m

To Find:

Force of Gravitation between any two objects.

Maximum Force of Gravitation.

Solution:

The Law of Gravitation states that the force between two objects is directly proportional to their masses and inversely proportional to the square of the distance between them.

                                       $F = G~\cfrac{M*m}{r^2}$

According to the above definition,

Force of gravitation between BC is,

                       $F_{BC} = 6.673 * 10^{-11}\cfrac{40*20}{10^2} ~~~~~~~~\{~~~~G = 6.673 * 10^{-11} ~N m^2/kg^2\\F_{BC} = 6.673 * 10^{-11}~\cfrac{800}{100}\\F_{BC} = 6.673 * 10^{-11}*8\\F_{BC} = 53.38 * 10^{-11}~N$

Hence Force between Object B and C is $53.38 * 10^{-11}$.

Since the force is inversely proportional to the square of the distance between the objects. So for the maximum force, distance should be the least.

And, the least distance is between the objects B and C only.

Hence the maximum force of gravitation is between objects B and C which is $53.38 * 10^{-11}$.