Three of the exterior angles of an n-sided
polygon are 50° each, two of its interior
angles are 127° and 135°, and the remaining
interior angles are 173° each. Find the value of n.
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Answer:
the exterior angles have to sum to 360, all the way around
with exterior of 50 we have exterior of 150 so far and 360 - 150 = 210 left for exterior angles
exterior with 127 interior = 53
exterior with 135 = 45
so
210 - 53 - 45 = 112 left for exteriors
exterior with 173 = 180-173=7
112/7 = 16
so i have
16
+1
+1
+3
= 21 interior angles = n
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