Question

Three of the exterior angles of an n-sided
polygon are 50° each, two of its interior
angles are 127° and 135°, and the remaining
interior angles are 173° each. Find the value of n.
plz ask this ans urgent plz​

Answer 1

Answer:

21

Step-by-step explanation:

We know that the sum of the exterior angles of any polygon is always 360 degrees.

Here, 3 exterior angles are 50 deg. each and so their sum = 150 deg. Two other exterior angles are 180–127 or 53º and 180–135 or 45º. Therefore the sum of the 5 exterior angles is 150+53+45 = 248º.

The sum of the remaining exterior angles = 360–248 or 112º. These are of the 112/(180–173) = 112/7 = 16 angles.

Hence n = 5+16 or 21. Answer.

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Answer 2

Answer:

the exterior angles have to sum to 360, all the way around

with exterior of 50 we have exterior of 150 so far and 360 - 150 = 210 left for exterior angles

exterior with 127 interior = 53

exterior with 135 = 45

so

210 - 53 - 45 = 112 left for exteriors

exterior with 173 = 180-173=7

112/7 = 16

so i have

16

+1

+1

+3

= 21 interior angles = n