Question

Three one rupee coins are tossed together. write down all possible outcomes and also find the probability of getting two heads. please answer send me.

Answer 1

$\bold{Possible\:outcomes\:=>\:}$

Total number of possible outcomes = 8

$\bold{1.\:TTT}$

$\bold{2.\:HHH}$

$\bold{3.\:TTH}$

$\bold{4.\:HHT}$

$\bold{5.\:HTH}$

$\bold{6.\:THT}$

$\bold{7.\:THH}$

$\bold{8.\:HTT}$

$P(E) = \: \frac{no \: of \: favourable \: outcomes}{total \: no \: of \: possible \: outcomes}$

Number of favourable outcomes = 3

[HHT, HTH ,THH]

Total number of possible outcomes = 8

Therefore probability of getting two heads =>

$P(E) = \: \frac{3}{8}$

$\bold{Therefore\: probability\:of\:getting\:two\: heads\:=\:\frac{3}{8}}$

Answer 2

When three coins are tossed together, possible outcomes:-

1) HHH

2) HHT

3)HTT

4)THH

5)TTH

6)TTT

7)THT

8)HTH

So, the total outcomes are :- 8

Favourable outcomes (two heads) =1)HHT
2)THH
3)HTH

$\boxed{ \bf{probability = \frac{favourable \: outcomes}{total \: outcomes} }}$

=3/8

$\underline{\bf{NOTE}}$

Here, we have not taken HHH as a favourable outcome because the question asks for two heads. If it would have been $\sf\: atleast\:two\:heads$,then we would have included it.
__________________________

⏩Probability means chance. In other words we need to calculate the chances of any outcome coming.

⏩Probability is never greater than 1 .

⏩Probability is never smaller than 0 .

⏩P(getting an event) +P(not getting an event)=1