Question

three oxides of nirogen contauned 63.6%b,46.7% and 30.4% nirogen respectively .show that these figure illisutrate at the law of multiple propration​

Answer 1

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Oxide 1:

63.6 g nitrogen is attached to 36.4 g oxygen.

1 g nitrogen is attached to (36.4/ 63.6) g = 0.572 g oxygen.

Oxide 2:

46.7 g nitrogen is attached to 53.3 g oxygen

1 g nitrogen is attached to (53.3/46.7) g = 1.141 g oxygen.

Oxide 3:

30.4 g nitrogen is attached to 60.6 g oxygen.

1 g nitrogen is attached to (69.6/30.4) g = 2.289 g oxygen.

In three oxides ratio of amounts of oxygen attached to fixed amount nitrogen (1 g) is 0.572 : 1.141 : 2.289 = 1 : 2 : 4

As 1, 2 and 4 are small whole numbers, the results do not violate law of multiple proportion.

* I have answered the question as per your given data.

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