Question

three oxides of nirogen contauned 63.6%b,46.7% and 30.4% nirogen respectively .show that th,ese figure illisutrate at the law of multiple propration​

Answer 1

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(i)

Answer 2

Answer:

Oxide 1:

63.6 g nitrogen is attached to 36.4 g oxygen.

1 g nitrogen is attached to $\frac{36.4}{ 63.6}$ g = 0.572 g oxygen.

Oxide 2:

46.7 g nitrogen is attached to 53.3 g oxygen

1 g nitrogen is attached to $\frac{53.3}{46.7}$g = 1.141 g oxygen.

Oxide 3:

30.4 g nitrogen is attached to 60.6 g oxygen.

1 g nitrogen is attached to $\frac{69.6}{30.4}$g = 2.289 g oxygen.

In three oxides ratio of amounts of oxygen attached to fixed amount nitrogen (1 g) is 0.572 : 1.141 : 2.289 = 1 : 2 : 4