Question

Three painters completed 2/7, 1/5 and 3/10 a work each on three consecative days find out which painter did the most work in the three days
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Answer 1

Answer:

3/10 is the most work is done

Step-by-step explanation:

Day 1. 2/7=0.28

Day 2. 1/5=0.2

Day 3. 3/10= 0.3

Answer 2

first find LCM of 7,5,10 is 70 2/7×70=20/70 ,1/5×70=14/70,3/10×70=21/70. so 21/70 , 20/70, 14/70 so 4/10 is work more than others