Math, asked by juanpetas, 11 months ago

Three paintings,each measuring 1 3/4 meters high by 4/5 meters wide, are hung in the display space.what is the total area of the three paintings?

Answers

Answered by spiderman2019
2

Answer:

21/5 sq. m

Step-by-step explanation:

l = 1 3/4 m = 7/4 m.

b = 4/5 m.

Area of one painting = l * b = 7/4 * 4/5 = 7/5 sq.m.

Total area of 3 paintings = 3 * 7/5 = 21/5 sq. m

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