Question

Three pairs of triangle ABC are given,find the smallest angle a=3cm, b=4cm,c=6cm

Answer 1

Answer:

The smallest angle is $\angle A\approx 26.38^\circ$

Step-by-step explanation:

Use cosine law to find an angle:

$3^2=4^2+6^2-2(4)(6)\cos{A}\\\angle A\approx26.38^\circ\\\\4^2=3^2+6^2-2(3)(6)\cos{B}\\\\\angle B\approx36.34^\circ$

The last angle can be found using the triangle-angle-sum theorem

$26.38^\circ+36.34^\circ+\angle{C}=180^\circ\\\angle{C}=117.28^\circ$

Therefore, the smallest angle is $\angle A\approx 26.38^\circ$

Answer 2

Answer:

3+4+6=180 degree

13=180 degree

180/13= 13.846-< (average answer)

3=3×13.846

=41.538

4=4×13.846

=55.384

6=6×13.846

=83.076