Three parallel lines , l1 ,l2 and l3 are
drawn through the vertices A, B and C of
a square ABCD. If the distance between
l1 and l2 is 12, then the area of the square
ABCD is
Answers
Answered by
9
Answer:
the area of the square ABCD is 193 sq units
Step-by-step explanation:
Ref attached picture
∠EBA + ∠ABC + ∠CBF = 180° (straight line)
∠ABC = 90° ( angle of square)
=> ∠EBA + 90° + ∠CBF = 180°
=> ∠EBA + ∠CBF = 90°
=> ∠EBA = 90° - ∠CBF
=> ∠EBA = ∠BCF
∠AEB = ∠CFB = 90°
AB = BC (side of square)
=> ΔAEB ≅ BFC
=> AE = BF = 12
EB = CF = 7
AB² = BC² = 12² + 7² = 144 + 49 = 193
the area of the square ABCD is 193 sq units
Attachments:
Answered by
1
Answer:
This question is not complete! What's the distance between l2 and l3?
Step-by-step explanation:
Similar questions