Three particles A,B and C are thrown from the top of a tower with the same speed. A is thrown up, B is
thrown down and C is horizontally. They hit the ground with speeds VA, V and V, respectively then
a) VA<V Vc b) V=V>VC c) VAV =VC d) V >V=VC [ ]
Answers
Answered by
2
Answer:
hey here is your answer
Explanation:
The particle which is thrown hrizontally will take time of √2H/g
The particle which is thrown downward will take time g
I think answer is V then v and then VA
Answered by
1
Answer:
solved
Explanation:
choose answer a) VA< V , Vc
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