Physics, asked by laksmiidevi818, 10 months ago

Three particles A,B and C are thrown from the top of a tower with the same speed. A is thrown up, B is
thrown down and C is horizontally. They hit the ground with speeds VA, V and V, respectively then
a) VA<V Vc b) V=V>VC c) VAV =VC d) V >V=VC [ ]​

Answers

Answered by rohan258060
2

Answer:

hey here is your answer

Explanation:

The particle which is thrown hrizontally will take time of √2H/g

The particle which is thrown downward will take time g

I think answer is V then v and then VA

Answered by azizalasha
1

Answer:

solved

Explanation:

choose answer a)  VA< V , Vc

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