Physics, asked by recreatixn8654, 8 months ago

Three particles A, B and C are thrown from the top of a
tower with the same speed. A is thrown up, B is thrown
down and C is horizontally. They hit the ground with speeds
vA, vB and vC respectively then,
(a) vA = vB = vC (b) vA = vB > vC
(c) vB > vC > vA (d) vA > vB = vC

Answers

Answered by iamrabinson

5

Answer:

Explanation:

Answer is (a) . see the pic for concept.

u can olso solve it by using equations of motion .. but whenever speed is asked energy conservation is fastest

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