Physics, asked by mythrihasini, 8 months ago

Three particles A,B and C start from the origin at the same time A with velocity 'a' along X-axis B with velocity 'b' along Y-axis and C is with velocity 'c' in xy-plane along a line x=y.The magnitude of c,so that they always remain collinear is _____​

Answers

Answered by soumya1145
4

Answer:

\frac{\sqrt{2}{ab} }{a+b}

Explanation:

slope comes out to be

\frac{b-0}{0-a} = \frac{\frac{c}{\sqrt{2} } -0}{\frac{c}{\sqrt{2}}-a}

A_________C_____________B

(a,0)             (\frac{c}{\sqrt{2} },\frac{c}{\sqrt{2} })                      (0,b)

bc/\sqrt{2} - ab = - ac/\sqrt{2}

(a+b)*\frac{c}{\sqrt{2} }= ab

c= ab \sqrt{2}/(a+b)

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