Question

three particles a b c are situated at the vertex of an equilateral triangle ABC of side at time t is equal to zero each of the particles move with constant speed v a always as if velocity along a b b and angle C and C and MCA at what time will be for articles meet each other​

Answer 1

Answer:

sorry buddy can't understand

Explanation:

sorry buddy can't understand

Answer 2

Answer:

so the time taken is 2d/3v

Explanation:

Velocity of A is v along AB. The velocity of B is along BC.Its component

along BA is vcos60=  v/2

. Thus, the separation AB decreases at the rate

v-(-v/2)=3v/2

 

Since, this rate is constant, the time taken in reducing the separation AB from d to zero is

t= d/ (3v/2)

 =2d/3v

so the time taken is 2d/3v

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