Question

Three particles each having a charge of 10C are placed at the corners of an equilateral triangle of Side 10cm. What is the electrostatic potential energy of the system​

Answer 1

Answer: 27J

Explanation:27J is right

Answer 2

Explanation:

Potential energy = [(k ∙ Q1Q2)/r]

here q = 10μc

at corners of equilateral triangle r =

10 cm = 0.1m

∴ Potential energy for pals of charge

= [{k(q ∙ q)}/r] + [{k(q ∙ q)}/r] + [{k(q ∙ q)}/r]

= [(3k)/r]q2

= 3 × [1/(4π∈0)] × (1/0.1) × (10 × 10–6)2

=3 × 9 × 109 × 10 × 10–10

= 27J