Question

Three particles, each of 10 g are located at the
corners of an equilateral triangle of side 5 cm.
Determine the moment of inertia of this system
about an axis passing through one corner of the
triangle and perpendicular to the plane of the
triangle.
(Ans. 5 x 10-5 kgm?)​

Answer 1

Explanation:

Moment of inertia due to mass passing through the axis is zero.

Moment of inertia due to other two mass=

2mr

2

=2×10

−2

×25×10

−4

=5×10

−5

Kgm

2