Three particles each of mas are kept at vertical vertex of equilateral triangle of side l the gravitational field at centre due to this particle is
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Let ABC be the triangle.
Let mass m be situated at the midpoint of side BC.
It experiences equal and opposite force due to particle at B and C
Hence the total force experienced by the mass is only due to A
Which equal to Gm^2/(a×sqrt(3)/4))^2
4Gm^2/3a^2
Let mass m be situated at the midpoint of side BC.
It experiences equal and opposite force due to particle at B and C
Hence the total force experienced by the mass is only due to A
Which equal to Gm^2/(a×sqrt(3)/4))^2
4Gm^2/3a^2
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