Physics, asked by vipbhai, 10 months ago

Three particles each of mas are kept at vertical vertex of equilateral triangle of side l the gravitational field at centre due to this particle is

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Answered by Anonymous
0
Let ABC be the triangle.

Let mass m be situated at the midpoint of side BC.

It experiences equal and opposite force due to particle at B and C

Hence the total force experienced by the mass is only due to A

Which equal to Gm^2/(a×sqrt(3)/4))^2

4Gm^2/3a^2
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