Three particles each of mass 10 g are placed at the vertices of an equilatral triangle of side 30 cm. Find Distance of its centre of mass from any of its vertex
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Center of mass will be at the Centroid of the equilateral triangle.
Length of perpendicular = √[a²-(a/2)²] = (a√3)/2
The centroid divides the perpendicular into 2:1
distance of center of mass from vertex = (2/3)×(a√3)/2 =a/√3
= 30/√3 = 10√3 cm
Length of perpendicular = √[a²-(a/2)²] = (a√3)/2
The centroid divides the perpendicular into 2:1
distance of center of mass from vertex = (2/3)×(a√3)/2 =a/√3
= 30/√3 = 10√3 cm
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