Question

three particles each of mass 10 g placed at the vertices of an equilateral triangle of side 30 cm. find (1).distance of its centre of mass from any of its vertices.

Answer 1

For symmetry, it comes that center of mass located at the center of circum circle of  triangle is radius of circum circle.
Equilateral traingle:
R=(√3/3)xa
=(√3/3)xo.3
=√3/10=0.173m
Therefore , distance of its centre of mass from any of its vertices is 0.173m