Physics, asked by Bunty6380, 1 year ago

Three particles each of mass m are palced at the corners of an equilateral triangle of side b. The gravitational potential energy of the system of particle is

Answers

Answered by ravi8682

0

Answer:

Answer should be 3Gm^2/b

Explanation:

as gravitational potential energy=Gm1m2/r^2 ,

where 'r' is the distance between the masses.

Attachments:

Answered by ishwarsinghdhaliwal

2

The gravitational potential energy of the system of particle is = -3Gm²/b

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