three particles each of mass m are placed at the corners of an equilateral triangle of side 'a'. energy is given to their system so that they are now at the corners of an equilateral traingle of side '2a'. energy given to the system in this process is ....
this is a question of gravitation
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FG=Gm2(3√r2)2
Force on the given mass by the two masses on the same line will cancel out. So the net force on the given mass will be due to the mass placed on the third corner. The distance between these two masses is equal to the median of the triangle which is a√3/2. Now use Newton's law of gravitation to calculate the force. F = Gm^2/ (a√3/2)^2 = 4Gm^2/3a^2
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